22=(5/b^2)*b^3

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Solution for 22=(5/b^2)*b^3 equation: 


D( b )

b^2 = 0

b^2 = 0

b^2 = 0

1*b^2 = 0 // : 1

b^2 = 0

b = 0

b in (-oo:0) U (0:+oo)

22 = (5/(b^2))*b^3 // - (5/(b^2))*b^3

22-((5/(b^2))*b^3) = 0

22-5*b = 0

22-5*b = 0 // - 22

-5*b = -22 // : -5

b = -22/(-5)

b = 22/5

b = 22/5

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